Math Practice Problems - Stem And Leaf Plots

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Stem And Leaf Plots - Sample Math Practice Problems

The math problems below can be generated by MathScore.com, a math practice program for schools and individual families. References to complexity and mode refer to the overall difficulty of the problems as they appear in the main program. In the main program, all problems are automatically graded and the difficulty adapts dynamically based on performance. Answers to these sample questions appear at the bottom of the page. This page does not grade your responses.

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Complexity=5

Calculate the mean of the data represented by the following stem and leaf plots.

Data Values
Stem	Leaf
0	2
5	3, 5
9	1

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Data Values
Stem	Leaf
0	0
1	2, 4
2	5
7	8

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Complexity=8

Calculate the mean of the data represented by the following stem and leaf plots.

Data Values
Stem	Leaf
1	1
3	0
4	3
7	4

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Data Values
Stem	Leaf
0	6
2	0, 1
3	4
4	6
5	8
6	3
8	7

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Answers

Complexity=5

Calculate the mean of the data represented by the following stem and leaf plots.

Problem

Correct Answer

Your Answer

Data Values
Stem	Leaf
0	2
5	3, 5
9	1

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Solution
Arithmetic Mean = sum of values / number of values = (2 + 53 + 55 + 91) / 4 = 50.3
Median = middle term of values = middle of (2, 53, 55, 91) = (53 + 55)/2 =54
Range = largest value - smallest value = 91 - 2 = 89
Lower Quartile = median of lower half of data values = middle of (2, 53) = (2 + 53) / 2 = 27.5
Upper Quartile = median of upper half of data values = middle of (55, 91) = (55 + 91) / 2 = 73

Problem

Correct Answer

Your Answer

Data Values
Stem	Leaf
0	0
1	2, 4
2	5
7	8

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Solution
Arithmetic Mean = sum of values / number of values = (0 + 12 + 14 + 25 + 78) / 5 = 25.8
Median = middle term of values = middle of (0, 12, 14, 25, 78) = 14
Range = largest value - smallest value = 78 - 0 = 78
Lower Quartile = median of lower half of data values = middle of (0, 12) = (0 + 12) / 2 = 6
Upper Quartile = median of upper half of data values = middle of (25, 78) = (25 + 78) / 2 = 51.5

Complexity=8

Calculate the mean of the data represented by the following stem and leaf plots.

Problem

Correct Answer

Your Answer

Data Values
Stem	Leaf
1	1
3	0
4	3
7	4

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Solution
Arithmetic Mean = sum of values / number of values = (11 + 30 + 43 + 74) / 4 = 39.5
Median = middle term of values = middle of (11, 30, 43, 74) = (30 + 43)/2 =36.5
Range = largest value - smallest value = 74 - 11 = 63
Lower Quartile = median of lower half of data values = middle of (11, 30) = (11 + 30) / 2 = 20.5
Upper Quartile = median of upper half of data values = middle of (43, 74) = (43 + 74) / 2 = 58.5

Problem

Correct Answer

Your Answer

Data Values
Stem	Leaf
0	6
2	0, 1
3	4
4	6
5	8
6	3
8	7

Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Solution
Arithmetic Mean = sum of values / number of values = (6 + 20 + 21 + 34 + 46 + 58 + 63 + 87) / 8 = 41.9
Median = middle term of values = middle of (6, 20, 21, 34, 46, 58, 63, 87) = (34 + 46)/2 =40
Range = largest value - smallest value = 87 - 6 = 81
Lower Quartile = median of lower half of data values = middle of (6, 20, 21, 34) = (20 + 21) / 2 = 20.5
Upper Quartile = median of upper half of data values = middle of (46, 58, 63, 87) = (58 + 63) / 2 = 60.5

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