Math Practice Problems - Rectangular Solids

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Rectangular Solids - Sample Math Practice Problems

The math problems below can be generated by MathScore.com, a math practice program for schools and individual families. References to complexity and mode refer to the overall difficulty of the problems as they appear in the main program. In the main program, all problems are automatically graded and the difficulty adapts dynamically based on performance. Answers to these sample questions appear at the bottom of the page. This page does not grade your responses.

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Complexity=2

Find the surface area and volume. Answer with proper units. To represent m², use "sq m". Sample answer: "5 sq m". To represent m³, use "cu m".

Answers

Complexity=1

Find the surface area and volume. Answer with proper units. To represent m², use "sq m". Sample answer: "5 sq m". To represent m³, use "cu m".

#	Problem	Correct Answer	Your Answer
1		surface area = volume =
Solution The surface area is the area of the six sides. This is twice the area of the three different kinds of sides. = 2 × ((2m × 1m) + (1m × 1m) + (1m × 2m)) = 10 m². V=lwh (length × width × height) = 1m × 2m × 1m = 2 m³.

#	Problem	Correct Answer	Your Answer
2		surface area = volume =
Solution The surface area is the area of the six sides. This is twice the area of the three different kinds of sides. = 2 × ((2in × 3in) + (3in × 2in) + (2in × 2in)) = 32 in². V=lwh (length × width × height) = 2in × 2in × 3in = 12 in³.

Complexity=2

Find the surface area and volume. Answer with proper units. To represent m², use "sq m". Sample answer: "5 sq m". To represent m³, use "cu m".

#	Problem	Correct Answer	Your Answer
1		surface area = volume =
Solution The surface area is the area of the six sides. This is twice the area of the three different kinds of sides. = 2 × ((3cm × 1cm) + (1cm × 2cm) + (2cm × 3cm)) = 22 cm². V=lwh (length × width × height) = 2cm × 3cm × 1cm = 6 cm³.

#	Problem	Correct Answer	Your Answer
2		surface area = volume =
Solution The surface area is the area of the six sides. This is twice the area of the three different kinds of sides. = 2 × ((8m × 5m) + (5m × 8m) + (8m × 8m)) = 288 m². V=lwh (length × width × height) = 8m × 8m × 5m = 320 m³.

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