Math Practice Online: MathScore.com

Math Practice Online > free > lessons > New York > 7th grade > Circle Circumference

If your child needs math practice, click here.

These sample problems below for Circle Circumference were generated by the MathScore.com engine.

Sample Problems For Circle Circumference


Complexity=4, Mode=exact

Find the circumference in terms of π. Type "pi" in for π so that a correct answer would look like 7pi m.
1.   Circumference:
2.   Circumference:

Complexity=6, Mode=exact

Find the circumference in terms of π. Type "pi" in for π so that a correct answer would look like 7pi m.
1.   Circumference:
2.   Circumference:

Complexity=8, Mode=exact

Find the circumference in terms of π. Type "pi" in for π so that a correct answer would look like 7pi m.
1.   Circumference:
2.   Circumference:

Complexity=4, Mode=fraction

Find the circumference. Use 22/7 as an approximation for π. A correct answer would look like 14.5 cm.
1.   Circumference:
2.   Circumference:

Complexity=4

Find the circumference. Use 3.14 as an approximation for π. A correct answer would look like 4.78 in.
1.   Circumference:
2.   Circumference:

Answers


Complexity=4, Mode=exact

Find the circumference in terms of π. Type "pi" in for π so that a correct answer would look like 7pi m.
#ProblemCorrect AnswerYour Answer
1 Circumference:
Solution
Circumference = π × diameter
C = πd
Since we have that the radius is 1 m, we multiply it by 2 to get the diameter which then is 2 m.
Plugging values into the equation, we have:
C = π(2 m)
C = 2π m
#ProblemCorrect AnswerYour Answer
2 Circumference:
Solution
Circumference = π × diameter
C = πd
Plugging values into the equation, we have:
C = π(4 km)
C = 4π km

Complexity=6, Mode=exact

Find the circumference in terms of π. Type "pi" in for π so that a correct answer would look like 7pi m.
#ProblemCorrect AnswerYour Answer
1 Circumference:
Solution
Circumference = π × diameter
C = πd
Plugging values into the equation, we have:
C = π(2 mi)
C = 2π mi
#ProblemCorrect AnswerYour Answer
2 Circumference:
Solution
Circumference = π × diameter
C = πd
Since we have that the radius is 4 mm, we multiply it by 2 to get the diameter which then is 8 mm.
Plugging values into the equation, we have:
C = π(8 mm)
C = 8π mm

Complexity=8, Mode=exact

Find the circumference in terms of π. Type "pi" in for π so that a correct answer would look like 7pi m.
#ProblemCorrect AnswerYour Answer
1 Circumference:
Solution
Circumference = π × diameter
C = πd
Since we have that the radius is 4 mm, we multiply it by 2 to get the diameter which then is 8 mm.
Plugging values into the equation, we have:
C = π(8 mm)
C = 8π mm
#ProblemCorrect AnswerYour Answer
2 Circumference:
Solution
Circumference = π × diameter
C = πd
Plugging values into the equation, we have:
C = π(2 km)
C = 2π km

Complexity=4, Mode=fraction

Find the circumference. Use 22/7 as an approximation for π. A correct answer would look like 14.5 cm.
#ProblemCorrect AnswerYour Answer
1 Circumference:
Solution
Circumference = π × diameter
C = πd
Since we have that the radius is 14 yd, we multiply it by 2 to get the diameter which then is 28 yd.
Plugging values into the equation, we have:
C = π(28 yd)
C = (22/7) × (28 yd)
C = 88 yd
#ProblemCorrect AnswerYour Answer
2 Circumference:
Solution
Circumference = π × diameter
C = πd
Since we have that the radius is 21 mm, we multiply it by 2 to get the diameter which then is 42 mm.
Plugging values into the equation, we have:
C = π(42 mm)
C = (22/7) × (42 mm)
C = 132 mm

Complexity=4

Find the circumference. Use 3.14 as an approximation for π. A correct answer would look like 4.78 in.
#ProblemCorrect AnswerYour Answer
1 Circumference:
Solution
Circumference = π × diameter
C = πd
Plugging values into the equation, we have:
C = π(2 in)
C = 3.14 × (2 in)
6.28 in
#ProblemCorrect AnswerYour Answer
2 Circumference:
Solution
Circumference = π × diameter
C = πd
Since we have that the radius is 2 mi, we multiply it by 2 to get the diameter which then is 4 mi.
Plugging values into the equation, we have:
C = π(4 mi)
C = 3.14 × (4 mi)
12.56 mi

MathScore.com

Copyright Accurate Learning Systems Corporation 2008.
MathScore is a registered trademark.