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These sample problems below for Stem And Leaf Plots were generated by the MathScore.com engine.

Sample Problems For Stem And Leaf Plots


Complexity=5

Calculate the mean of the data represented by the following stem and leaf plots.
1.  
Data Values
StemLeaf
07
32
64
84, 5
Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:
2.  
Data Values
StemLeaf
23
66
82
100, 0
Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Complexity=8

Calculate the mean of the data represented by the following stem and leaf plots.
1.  
Data Values
StemLeaf
07
20, 2
35
98
Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:
2.  
Data Values
StemLeaf
44
62
76
96
Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:

Answers


Complexity=5

Calculate the mean of the data represented by the following stem and leaf plots.
#ProblemCorrect AnswerYour Answer
1
Data Values
StemLeaf
07
32
64
84, 5
Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:
Solution
Arithmetic Mean = sum of values / number of values = (7 + 32 + 64 + 84 + 85) / 5 = 54.4
Median = middle term of values = middle of (7, 32, 64, 84, 85) = 64
Range = largest value - smallest value = 85 - 7 = 78
Lower Quartile = median of lower half of data values = middle of (7, 32) = (7 + 32) / 2 = 19.5
Upper Quartile = median of upper half of data values = middle of (84, 85) = (84 + 85) / 2 = 84.5
#ProblemCorrect AnswerYour Answer
2
Data Values
StemLeaf
23
66
82
100, 0
Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:
Solution
Arithmetic Mean = sum of values / number of values = (23 + 66 + 82 + 100 + 100) / 5 = 74.2
Median = middle term of values = middle of (23, 66, 82, 100, 100) = 82
Range = largest value - smallest value = 100 - 23 = 77
Lower Quartile = median of lower half of data values = middle of (23, 66) = (23 + 66) / 2 = 44.5
Upper Quartile = median of upper half of data values = middle of (100, 100) = (100 + 100) / 2 = 100

Complexity=8

Calculate the mean of the data represented by the following stem and leaf plots.
#ProblemCorrect AnswerYour Answer
1
Data Values
StemLeaf
07
20, 2
35
98
Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:
Solution
Arithmetic Mean = sum of values / number of values = (7 + 20 + 22 + 35 + 98) / 5 = 36.4
Median = middle term of values = middle of (7, 20, 22, 35, 98) = 22
Range = largest value - smallest value = 98 - 7 = 91
Lower Quartile = median of lower half of data values = middle of (7, 20) = (7 + 20) / 2 = 13.5
Upper Quartile = median of upper half of data values = middle of (35, 98) = (35 + 98) / 2 = 66.5
#ProblemCorrect AnswerYour Answer
2
Data Values
StemLeaf
44
62
76
96
Mean:
Median:
Range:
Lower Quartile:
Upper Quartile:
Solution
Arithmetic Mean = sum of values / number of values = (44 + 62 + 76 + 96) / 4 = 69.5
Median = middle term of values = middle of (44, 62, 76, 96) = (62 + 76)/2 =69
Range = largest value - smallest value = 96 - 44 = 52
Lower Quartile = median of lower half of data values = middle of (44, 62) = (44 + 62) / 2 = 53
Upper Quartile = median of upper half of data values = middle of (76, 96) = (76 + 96) / 2 = 86

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