Circle Area Sample Problems

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These sample problems below for Circle Area were generated by the MathScore.com engine.

Sample Problems For Circle Area

Find the area in terms of π. Type "pi" in for π so that a correct answer would look like 7pi sq m

Area:

Find the area in terms of π. Type "pi" in for π so that a correct answer would look like 7pi sq m

Area:

Find the area in terms of π. Type "pi" in for π so that a correct answer would look like 7pi sq m

Area:

Find the area. Use 22/7 as an approximation for π. A correct answer would look like 14.5 sq cm.

Area:

Find the area. Use 3.14 as an approximation for π. A correct answer would look like 4.785 sq in

Area:

Find the area in terms of π. Type "pi" in for π so that a correct answer would look like 7pi sq m

#	Problem	Correct Answer	Your Answer
1		Area:
Solution Area = π × (radius)² A = πr² Since we have that the diameter is 4 m, we divide it by 2 to get the radius which then is 2 m. Plugging values into the equation, we have: A = π(2 m)² A = &pi(4 m²) A = 4π m²

#	Problem	Correct Answer	Your Answer
2		Area:
Solution Area = π × (radius)² A = πr² Since we have that the diameter is 3 mm, we divide it by 2 to get the radius which then is 1.5 mm. Plugging values into the equation, we have: A = π(1.5 mm)² A = &pi(2.25 mm²) A = 2.25π mm²

Find the area in terms of π. Type "pi" in for π so that a correct answer would look like 7pi sq m

#	Problem	Correct Answer	Your Answer
1		Area:
Solution Area = π × (radius)² A = πr² Since we have that the diameter is 4 km, we divide it by 2 to get the radius which then is 2 km. Plugging values into the equation, we have: A = π(2 km)² A = &pi(4 km²) A = 4π km²

#	Problem	Correct Answer	Your Answer
2		Area:
Solution Area = π × (radius)² A = πr² Since we have that the diameter is 3 m, we divide it by 2 to get the radius which then is 1.5 m. Plugging values into the equation, we have: A = π(1.5 m)² A = &pi(2.25 m²) A = 2.25π m²

Find the area in terms of π. Type "pi" in for π so that a correct answer would look like 7pi sq m

#	Problem	Correct Answer	Your Answer
1		Area:
Solution Area = π × (radius)² A = πr² Since we have that the diameter is 1 cm, we divide it by 2 to get the radius which then is 0.5 cm. Plugging values into the equation, we have: A = π(0.5 cm)² A = &pi(0.25 cm²) A = 0.25π cm²

#	Problem	Correct Answer	Your Answer
2		Area:
Solution Area = π × (radius)² A = πr² Since we have that the diameter is 2 cm, we divide it by 2 to get the radius which then is 1 cm. Plugging values into the equation, we have: A = π(1 cm)² A = &pi(1 cm²) A = 1π cm²

Find the area. Use 22/7 as an approximation for π. A correct answer would look like 14.5 sq cm.

#	Problem	Correct Answer	Your Answer
1		Area:
Solution Area = π × (radius)² A = πr² Since we have that the diameter is 21 mi, we divide it by 2 to get the radius which then is 10.5 mi. Plugging values into the equation, we have: A = π(10.5 mi)² A = (22/7) × (110.25 mi²) 346.5 mi²

#	Problem	Correct Answer	Your Answer
2		Area:
Solution Area = π × (radius)² A = πr² Plugging values into the equation, we have: A = π(14 in)² A = (22/7) × (196 in²) 616 in²

Find the area. Use 3.14 as an approximation for π. A correct answer would look like 4.785 sq in

#	Problem	Correct Answer	Your Answer
1		Area:
Solution Area = π × (radius)² A = πr² Plugging values into the equation, we have: A = π(4 m)² A = 3.14 × (16 m²) 50.24 m²

#	Problem	Correct Answer	Your Answer
2		Area:
Solution Area = π × (radius)² A = πr² Since we have that the diameter is 2 yd, we divide it by 2 to get the radius which then is 1 yd. Plugging values into the equation, we have: A = π(1 yd)² A = 3.14 × (1 yd²) 3.14 yd²