Solution
Probability that all 3 pieces are highlighted:
P(1st piece highlighted) = 1/4. P(2nd piece highlighted) = 4/5. P(3rd piece highlighted) = 1/3. P(all highlighted) = 1/4 × 4/5 × 1/3 = 1/15.
Odds of choosing at least one unhighlighted
piece: P(at least one piece unhighlighted) = 1 -
P(all highlighted) = 1 - 1/15 = 14/15. Odds(at least one piece unhighlighted) = 14:(15 - 14) = 14:1.
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